#### qwertychick

##### New member

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- Dec 16, 2020

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(α C k)(k C m) = [α C m] [ (α − m) C (k − m) ].

Please help

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- Thread starter qwertychick
- Start date

- Joined
- Dec 16, 2020

- Messages
- 1

(α C k)(k C m) = [α C m] [ (α − m) C (k − m) ].

Please help

- Joined
- Jan 29, 2005

- Messages
- 11,391

This appears to be an really ill-defined problem. It says that if [imath]\alpha\in\mathbb{R}~\&~\{k,n\}\subset\mathbb{N}^+[/imath] then....

(α C k)(k C m) = [α C m] [ (α − m) C (k − m) ].

Please help

But that would mean that [imath]^{\sqrt[3]{15}}\mathcal{C}_{5}[/imath] is defined. I don't recognize that a in any use of combinations.

Please review the post and either correct or explain what is meant.

- Joined
- Oct 30, 2021

- Messages
- 580

This appears to be an really ill-defined problem. It says that if [imath]\alpha\in\mathbb{R}~\&~\{k,n\}\subset\mathbb{N}^+[/imath] then....

But that would mean that [imath]^{\sqrt[3]{15}}\mathcal{C}_{5}[/imath] is defined. I don't recognize that a in any use of combinations.

Please review the post and either correct or explain what is meant.

en.wikipedia.org

- Joined
- Oct 30, 2021

- Messages
- 580

Forgot to mention that the link points to the## Binomial coefficient - Wikipedia

en.wikipedia.org