Completing a square to write equation in circle standard form

Joined
May 12, 2019
Messages
189
I used this from your site to help, here

I want to make sure I've correctly solved the below.

Question:
[MATH]x^2+y^2-6x+4y+4=0[/MATH]
Working:
[MATH]x^2-6x+y^2+4y+4=0[/MATH]
[MATH](x^2-6x+3^2)+(y^2+4y+2^2)+4=3^2+2^2[/MATH]
[MATH](x-3)^2+(y+2)^2=9[/MATH]
[MATH](3,-2) , r=3[/MATH]
 
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