complex fraction: solve [49- 1/y^2]/[7+1/y] = 1 for Y

[dayton1]

I am still stuck on this one...any help?

[49- 1/y^2]/[7+1/y] = 1 *solve for Y

so I multiply both sides by y^2 to give me [49y^2-1]/[7y^2+y]=1 ?????

I don't know what to do now.

 

[stapel]

[49- 1/y^2]/[7+1/y] = 1 *solve for Y

If I understand you correctly, the equation is as follows:

. . . . .[49 - 1/y²] / [7 + 1/y] = 1

Since you have "(fraction) = (number)", then you can multiply through to clear the one (messy) denominator:

. . . . .49 - 1/y² = 1(7 + 1/y)

. . . . .49 - 1/y² = 7 + 1/y

You then multiplied through by y², which clears the remaining denominators:

. . . . .49y² - 1 = 7y² + y

Now gather all the terms on one side of the "equals" sign (I'd move to the right), and then solve the resulting quadratic equation.

Eliz.

 

[dayton1]

Thanks Eliz!