Complex numbers

[Anthonyk2013]

Z1-Z2 Z1=2+j4 Z2=3-j
(2-3)+(j4-j)
=-1+j3

is the above correct?

 

[pka]

Z1-Z2
Z1=2+j4 & Z2=3-j
(2-3)+(j4-j)
=-1+j3
is the above correct?

NO!
\(\displaystyle (2+4i)-(3-i)=(2-3)+(4+1)i=~?\)

 

[Anthonyk2013]

NO!
\(\displaystyle (2+4i)-(3-i)=(2-3)+(4 +1 )i=~?\)

How does -i change to +i?

 

[pka]

How does -i change to +i?

Look at the OP.
You posted \(\displaystyle z_1-z_2\) that is subtraction.

In your work you did \(\displaystyle z_1+z_2\). Now which is it?

 

[lookagain]

Z1-Z2 Z1=2+j4 Z2=3-j (2-3)+(j4-j)=-1+j3is the above correct?

Anthony, use "i" for \(\displaystyle \sqrt{-1}.\)Don't type "j4," "j3," etc. \(\displaystyle \ \ \) Those are not products of a variable and a constant. Instead, type the constant in front as it should be the coefficient for the variable.It's better to put your equations on separate lines, especially if you are unable to place more spaces between them.I understand your limitations in typing underscores in regular typing, as you typed"Z1" instead of "\(\displaystyle z_1,\)" for instance.\(\displaystyle z_1 - z_2\)\(\displaystyle z_1 = 2 + 4i\)\(\displaystyle z_2 = 3 - i\)\(\displaystyle (2 - 3) - (4 - (-1))i\)\(\displaystyle \cdot\)\(\displaystyle \cdot\)\(\displaystyle \cdot\)