Complimentary and Supplementary

RoseOfStone241

New member
Joined
Sep 5, 2006
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9
The supp. of an angle is 60 degrees less than twice the supplement of the complement of the angle. Finmd the measure of the complement.

I've tried numerous things. One item I tried was:

(180 -x) = 2(180-x-(90-x))-60

But obviously that's completely wrong because it doesn't match the correct answer.. :p

Any suggestions?
 
It looks like you are using "x" to stand for the measure of the angle.

Then "180 - x" is the supplement, and "90 - x" is the complement.

The supplement of the complement then is "180 - (90 - x)". (You have an extra "x" in there.)

Then the equation is:

. . . . .180 - x = 2[180 - (90 - x)] - 60

See if that works.

Eliz.
 
you were close ...

The supp. of an angle is 60 degrees less than twice the supplement of the complement of the angle.

180 - x = 2[180 - (90 - x)] - 60

try this equation ... don't forget that the problem asks for the angle's complement (90-x).
 
Yes!! It worked AND it made sense! Lol.

Thanks so much for your help Eliz and Skeeter! ^-^

Gotta love those silly mistakes! :D
 
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