F flakine Junior Member Joined Aug 24, 2005 Messages 78 Aug 31, 2005 #1 Find f o g o h, where f(x)= √(1-x) g(x) 1-x^2 h(x)=1+√x This is where I am: g(h(x)) 1-(1+√x)^2 1-(1+2√x+x) 1-1-2√x-x g(x)=-2√x-x f(g(x))=√(1+(-2√(x)-x) What am I doing wrong?
Find f o g o h, where f(x)= √(1-x) g(x) 1-x^2 h(x)=1+√x This is where I am: g(h(x)) 1-(1+√x)^2 1-(1+2√x+x) 1-1-2√x-x g(x)=-2√x-x f(g(x))=√(1+(-2√(x)-x) What am I doing wrong?
A askmemath New member Joined Apr 28, 2005 Messages 31 Aug 31, 2005 #2 You've copied the signs wrong!! f(x) = sqrt(1-x) = sqrt( 1 - (-2sqrtX - X)) = sqrt( 1 + 2sqrtX + X) = sqrt((1+ X)^2) = 1+X ta daaaa!!!
You've copied the signs wrong!! f(x) = sqrt(1-x) = sqrt( 1 - (-2sqrtX - X)) = sqrt( 1 + 2sqrtX + X) = sqrt((1+ X)^2) = 1+X ta daaaa!!!
F flakine Junior Member Joined Aug 24, 2005 Messages 78 Aug 31, 2005 #3 Are you sure that's it? The book has: 1+√(x)
A askmemath New member Joined Apr 28, 2005 Messages 31 Aug 31, 2005 #4 OOps my mistake it should read as sqrt((1+sqrt(x))^2) = 1 + sqrtX ta daaaaa!!!![/b]
M mathmike New member Joined Aug 26, 2005 Messages 22 Aug 31, 2005 #6 flakine said: Find f o g o h, where f(x)= √(1-x) g(x) 1-x^2 h(x)=1+√x Click to expand... It is simlier other way around: f(g) = sqrt(1-(1-x^2)) = x, x>=0 f(g(h)) = 1 + sqrt(x)
flakine said: Find f o g o h, where f(x)= √(1-x) g(x) 1-x^2 h(x)=1+√x Click to expand... It is simlier other way around: f(g) = sqrt(1-(1-x^2)) = x, x>=0 f(g(h)) = 1 + sqrt(x)