Computing center of mass in triple integral

Win_odd Dhamnekar

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Aug 14, 2018
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Find the center of mass of the solid S with the given density function δ(x,y,z)\displaystyle \delta(x,y,z)

S={(x,y,z):0x1,0y1,0z1xy},δ(x,y,z)=1S=\{(x,y,z): 0 \leq x \leq1, 0 \leq y \leq 1, 0 \leq z \leq 1-x-y\}, \delta (x,y,z)= 1
How to answer this question?

When I tried to compute M, I got M=0.

How is that? :unsure::oops:
 
Find the center of mass of the solid S with the given density function δ(x,y,z)\displaystyle \delta(x,y,z)

S={(x,y,z):0x1,0y1,0z1xy},δ(x,y,z)=1S=\{(x,y,z): 0 \leq x \leq1, 0 \leq y \leq 1, 0 \leq z \leq 1-x-y\}, \delta (x,y,z)= 1
How to answer this question?

When I tried to compute M, I got M=0.

How is that? :unsure::oops:
Please show your work in detail so that we can catch your mistake.
 
You did this.

M=010101xydz dy dx\displaystyle M = \int_{0}^{1}\int_{0}^{1}\int_{0}^{1-x-y} dz \ dy \ dx

You should do this.

M=0101x01xydz dy dx\displaystyle M = \int_{0}^{1}\int_{0}^{1-x}\int_{0}^{1-x-y} dz \ dy \ dx
 
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