3. When computing the limit of a composition of functions, we can introduce a substitution. For example, consider:
. . . . .\(\displaystyle \displaystyle \lim_{x\, \rightarrow \, \infty}\, \ln\left(\dfrac{2}{x^3}\right)\)
Let \(\displaystyle \, u\, =\, \dfrac{2}{x^3}\, \) and note that, as \(\displaystyle \, x\, \rightarrow \, \infty,\, u\, \rightarrow \, 0^+.\,\) Thus, we can rewrite the limit (in terms of u only), as:
. . . . .\(\displaystyle \displaystyle \lim_{u\, \rightarrow \, 0^+}\, \ln(u)\)
a. What is the value of this limit?
b. Explain why u approaches 0 specifically from the right (hence the use of 0+).
c. Using this method, compute \(\displaystyle \, \displaystyle \lim_{\theta \, \rightarrow \, 0^-}\, 2^{\cot \left(\theta\right)}\)
I've attached a picture of my calculus question to this thread, although I'm not sure if it worked or if it is visible. If it worked, I would greatly appreciate some help!! I only need help with parts a and c. If someone could explain the steps, that would be wonderful!
. . . . .\(\displaystyle \displaystyle \lim_{x\, \rightarrow \, \infty}\, \ln\left(\dfrac{2}{x^3}\right)\)
Let \(\displaystyle \, u\, =\, \dfrac{2}{x^3}\, \) and note that, as \(\displaystyle \, x\, \rightarrow \, \infty,\, u\, \rightarrow \, 0^+.\,\) Thus, we can rewrite the limit (in terms of u only), as:
. . . . .\(\displaystyle \displaystyle \lim_{u\, \rightarrow \, 0^+}\, \ln(u)\)
a. What is the value of this limit?
b. Explain why u approaches 0 specifically from the right (hence the use of 0+).
c. Using this method, compute \(\displaystyle \, \displaystyle \lim_{\theta \, \rightarrow \, 0^-}\, 2^{\cot \left(\theta\right)}\)
I've attached a picture of my calculus question to this thread, although I'm not sure if it worked or if it is visible. If it worked, I would greatly appreciate some help!! I only need help with parts a and c. If someone could explain the steps, that would be wonderful!
Last edited by a moderator: