A container has the shape of an open right circular cone. The height of the container is 10 cm and the diameter of the opening is 10 cm. Water in the container is evaporating so that its depth h is changing at the constant rate of (-3/10) cm/hr.
**The volume of a cone of height h and radius r is given by V=(1/3)pi(r2)h
a.) Find the volume V of water in the container when h=5 cm.
b.) Find the rate of change of the volume of water in the container, with respect to time, when h=5 cm.
c.) Show that the rate of change of the volume of water in the container due to evaporation is directly proportional to the exposed surface area of the water. What is the constant of proportionality?
--Please help. I have no idea where to go with this problem. I'm not sure of how to draw pictures on here, but I have the best description of the cone that I could. Immediate help would be GREATLY appreciated!!
Thanks![/img]
**The volume of a cone of height h and radius r is given by V=(1/3)pi(r2)h
a.) Find the volume V of water in the container when h=5 cm.
b.) Find the rate of change of the volume of water in the container, with respect to time, when h=5 cm.
c.) Show that the rate of change of the volume of water in the container due to evaporation is directly proportional to the exposed surface area of the water. What is the constant of proportionality?
--Please help. I have no idea where to go with this problem. I'm not sure of how to draw pictures on here, but I have the best description of the cone that I could. Immediate help would be GREATLY appreciated!!
Thanks![/img]