Confused about expanding in a DE

Joined
May 30, 2020
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6
Hello,
I have a separable differential equation. After integrating, I am not sure how to expand. This is what I mean:
CamScanner 05-30-2020 17.17.55.jpg
For the second version, I left it un-expanded. It gives a different answer when I try find the constant.
Does anyone know which version to do?
Thanks in advance for the help :)
 
Hello,
I have a separable differential equation. After integrating, I am not sure how to expand. This is what I mean:
View attachment 19345
For the second version, I left it un-expanded. It gives a different answer when I try find the constant.
Does anyone know which version to do?
Thanks in advance for the help :)
Those are actually the "same".

\(\displaystyle C_1 * \sqrt{7} \) = C2
 
You have \(\displaystyle cos^{-1}(y/\sqrt{7})= \sqrt{7}(x+ c)\)
and then \(\displaystyle cos^{-1}(y/\sqrt{7})= \sqrt{7}x+ c\)

No, that's not correct- at least not for the same "c".
What is correct is that \(\displaystyle cos^{-1}(y/\sqrt{7})= \sqrt{7}x+ \sqrt{7}c\).
Of course, \(\displaystyle \sqrt{7}\) times an unknown constant is just another unknown constant but you really should use a different symbol, say "C" rather than"c":
\(\displaystyle cos^{-1}(y/\sqrt{7})= \sqrt{7}x+ C\).

Yes, "c" and "C" are different numbers.
 
You have \(\displaystyle cos^{-1}(y/\sqrt{7})= \sqrt{7}(x+ c)\)
and then \(\displaystyle cos^{-1}(y/\sqrt{7})= \sqrt{7}x+ c\)

No, that's not correct- at least not for the same "c".
What is correct is that \(\displaystyle cos^{-1}(y/\sqrt{7})= \sqrt{7}x+ \sqrt{7}c\).
Of course, \(\displaystyle \sqrt{7}\) times an unknown constant is just another unknown constant but you really should use a different symbol, say "C" rather than"c":
\(\displaystyle cos^{-1}(y/\sqrt{7})= \sqrt{7}x+ C\).

Yes, "c" and "C" are different numbers.
Ah i understand now so i would replace it with a different letter but it technically is the same, yes that makes sense thank you for your help
 
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