Confused with maths question involving the "t formula"

Beer soaked ramblings follow.
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I have let t = tan a for the first 3 parts (a, b and c), but I am confused with how I should do part d.
tanα=13\tan\alpha=-\frac{1}{3} and π2<α<π\frac{\pi}{2}<\alpha<\pi     \implies a=1a=1, b=3b=-3, & c=a2+b2c=\sqrt{a^2+b^2}.

Just plug and chug using the 1st three of the Double-Angle Identities and the 3rd of the Half-Angle Identities.
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Beer soaked ramblings follow.

tanα=13\tan\alpha=-\frac{1}{3} and π2<α<π\frac{\pi}{2}<\alpha<\pi     \implies a=1a=1, b=3b=-3, & c=a2+b2c=\sqrt{a^2+b^2}.

Just plug and chug using the 1st three of the Double-Angle Identities and the 3rd of the Half-Angle Identities.
View attachment 28406
Thank you very much!
 
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