AustrianSaurkraut
New member
- Joined
- May 6, 2021
- Messages
- 14
Determine the value of a so that f(x)=√(ax2-4) has a tangent with a slope of 2 at the point where x equals to 2
For this, I started with the attempting the derivative, and got
f'(x) = 1/2(ax2-4)-1/2 * 2ax
From here, I began to sub in the X value but got stuck as there are too many A's and paired with a negative exponent, how does one expand the bracket and allow the A's to be grouped?
For this, I started with the attempting the derivative, and got
f'(x) = 1/2(ax2-4)-1/2 * 2ax
From here, I began to sub in the X value but got stuck as there are too many A's and paired with a negative exponent, how does one expand the bracket and allow the A's to be grouped?
