Confussed when it comes to showing equation in terms of an independent variable

sinclairharry

New member
Joined
Mar 22, 2015
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17
Question:

Find the following derivatives. Express your answer in terms of the independent variables.

zs and zt where z = 3 x y - 4 x^2 y, x= 4s + 3t and y = 4s - 3t

My answer for zs is -16x^2 + x(12-32y) + 12y

i am told my derivative is correct yet i dont know how to put it in terms of s and t
could some please help cheers?
 
Question:

Find the following derivatives. Express your answer in terms of the independent variables.

zs and zt where z = 3 x y - 4 x^2 y, x= 4s + 3t and y = 4s - 3t

My answer for zs is -16x^2 + x(12-32y) + 12y

i am told my derivative is correct yet i dont know how to put it in terms of s and t
could some please help cheers?
Possibly the easiest (but most tedious) way is to just substitute for x and y and work it out, for example 12y=48s-36t. Then do the simplification.
 
Question:

Find the following derivatives. Express your answer in terms of the independent variables.

zs and zt where z = 3 x y - 4 x^2 y, x= 4s + 3t and y = 4s - 3t

My answer for zs is -16x^2 + x(12-32y) + 12y

i am told my derivative is correct yet i dont know how to put it in terms of s and t
could some please help cheers?
I am concerned about what you think '=' means.

In -16x^2 + x(12-32y) + 12y why not just replace x with 4s+3t and y with 4s-3t?
 
Question:

Find the following derivatives. Express your answer in terms of the independent variables.

zs and zt where z = 3 x y - 4 x^2 y, x= 4s + 3t and y = 4s - 3t

My answer for zs is -16x^2 + x(12-32y) + 12y

i am told my derivative is correct yet i dont know how to put it in terms of s and t
could some please help cheers?
You can also sub 4s+3t for x and 4s-3t for y in z = 3 x y - 4 x^2 y and then calculate zs and zt
 
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