snakefashion
New member
- Joined
- Apr 9, 2016
- Messages
- 1
I had a homework problem that asked if
was conservative. The partial derivatives are the same, and I got that part of the problem right, but it is not a conservative function. If C is the circle
,
., then
= 2*pi, not 0, like it would if the vector field was conservative (as t = 0 and t = 2*pi are at the same point). Can anyone explain why this vector field isn't conservative? How can its partial derivatives be the same if it's not a conservative function?



