Consider a function ? (?) = √?, get ? ′ (?) using a definition:

[imperatyvo]

f'(x) = lim [ (x+h-x) / h.(√(x+h) + √x) ]
f'(x) = lim [ 1 / (√(x+h) + √x) ]

what do I do with ℎ → 0 ?


f'(x) = 1 / (√(x+0) + √x)
f'(x) = 1 / (2√x)

 

[Deleted member 4993]

View attachment 22320

f'(x) = lim [ (x+h-x) / h.(√(x+h) + √x) ]
f'(x) = lim [ 1 / (√(x+h) + √x) ]

what do I do with ℎ → 0 ?


f'(x) = 1 / (√(x+0) + √x)
f'(x) = 1 / (2√x)

Looks good to me.

 

[imperatyvo]

Looks good to me.

Seriously ? Thanks for confirming, I was very unsure