Contingency Table: 2 inspectors examine same 153 units, agreeing on 23 "bad" units...

jules1234

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Contingency Table: 2 inspectors examine same 153 units, agreeing on 23 "bad" units...

Hello! I am having trouble setting up the contingency table for this problem



A company has an inspection program for defects. It is hoped that inspectors make the same decisions. To find out if inspector decisions are related or are independent they conducted an experiment.

In the experiment 153 units were inspected by Inspector A, and 111 were classified as "acceptable".

The second inspector, Inspector B, evaluated the same 153 units and classified 124 as "acceptable".

Of the items rejected by Inspector B, Inspector A agreed with 23. This is the observed number in the cell of the 2 x 2 table that is in the intersection of the second row and second column.

Calculate the chi-square test statistics used in the chi-squared test of independence. Give your answer to 3 decimal places, do not round up or down.

Note, you will first have to construct the contingency table from the information given.

Answer: 6.155




I believe that once set up I will know where to go but what iv got now is not working. this is what I have set up.

ABTotal
Accepted111124235
NOT Accepted23
Total153153

Now I don't know how to get the 23 incorporated because by putting 23 where I have it, the total does not add up. By not using the 23 at all I still get the wrong answer.
 

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Contingency Table Question

A
B
Total
Accepted
111
124
235
No t Accepted (Defective)
42
29
71
Total
153
153
306
Hi guys I am having trouble with the attached problem. I believe that once I get the contingency table set up right I will have no problem completing the table. Right now my contingency table is set up like the following (see above) however this dosnt give me the right answer and I dont know what to do with the 23.
 

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  • Screen Shot 2018-03-15 at 6.06.59 PM.jpg
    Screen Shot 2018-03-15 at 6.06.59 PM.jpg
    22.4 KB · Views: 1
ABTotal
Accepted
111124235
Not Accepted (Defective)
422971
Total153153306
Hi guys I am having trouble with the attached problem. I believe that once I get the contingency table set up right I will have no problem completing the table. Right now my contingency table is set up like the following (see above) however this dosnt give me the right answer and I dont know what to do with the 23.
How are you getting that the total deemed defective is 71, when you know that Inspectors A and B agreed on 23 of the defectives? ;)
 
Try setting up your table differently.
Column 1 = Accepted by A
Column 2 = Rejected by A
Row 1 = Accepted by B
Row 2 = Rejected by B.
 
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