D dopey9 New member Joined Jul 14, 2006 Messages 39 Nov 14, 2006 #1 f:[-1,1] -> R is defined as .........../ 1/ln(x) , x not equal be 0 f(x) = { ...........\ 0, x=0 How do I show this is continious? Thanks!
f:[-1,1] -> R is defined as .........../ 1/ln(x) , x not equal be 0 f(x) = { ...........\ 0, x=0 How do I show this is continious? Thanks!
pka Elite Member Joined Jan 29, 2005 Messages 11,978 Nov 14, 2006 #2 Ln(x) is not defined for \(\displaystyle x \le 0 .\)
D dopey9 New member Joined Jul 14, 2006 Messages 39 Nov 14, 2006 #3 forgot to put the mod sign sori i forgot to put the modulus sign on ...its meant ot be 1 / ln (|x|)
pka Elite Member Joined Jan 29, 2005 Messages 11,978 Nov 14, 2006 #4 \(\displaystyle \L \lim _{x \to 0} \ln \left( {\left| x \right|} \right) = - \infty \quad \Rightarrow \quad \lim _{x \to 0} \frac{1}{{\ln \left( {\left| x \right|} \right)}} = 0\) Draw a graph. You will see it!
\(\displaystyle \L \lim _{x \to 0} \ln \left( {\left| x \right|} \right) = - \infty \quad \Rightarrow \quad \lim _{x \to 0} \frac{1}{{\ln \left( {\left| x \right|} \right)}} = 0\) Draw a graph. You will see it!
