confusedcalculusstudent
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- Joined
- Jun 7, 2018
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I'm having trouble with this problem:
Is it possible to define f(0) in such a way that would make f(x)=sin(3x^2-3)/x^201 continuous at x=1? If so, what should f(0) be so that f(x) is continuous at x=1?
For starters, I thought that saying f(0) meant that x=0? (please correct me, I'm in an intro math class for a reason XD)
Assuming x=1, I plugged it in and got: sin(3(1)^2-3)/(1)^2-1 => sin(0)/0, which doesn't seem in line with what they're asking for
Assuming x=0, sin(3(0)^2-3)/(0)^2-1 => sin(-3)/-1... multiplied by 3/3, 3sin(-3)/-3, (can sinh/h=1 be invoked here? I tried that and got an answer of 3, but I don't know if that's correct or how to justify that with the question saying x=1)
I'm very confused, please help
Is it possible to define f(0) in such a way that would make f(x)=sin(3x^2-3)/x^201 continuous at x=1? If so, what should f(0) be so that f(x) is continuous at x=1?
For starters, I thought that saying f(0) meant that x=0? (please correct me, I'm in an intro math class for a reason XD)
Assuming x=1, I plugged it in and got: sin(3(1)^2-3)/(1)^2-1 => sin(0)/0, which doesn't seem in line with what they're asking for
Assuming x=0, sin(3(0)^2-3)/(0)^2-1 => sin(-3)/-1... multiplied by 3/3, 3sin(-3)/-3, (can sinh/h=1 be invoked here? I tried that and got an answer of 3, but I don't know if that's correct or how to justify that with the question saying x=1)
I'm very confused, please help