T thepie New member Joined Sep 11, 2009 Messages 2 Sep 11, 2009 #1 Find the x values (if any) at which f is not continuous. Is this discontinuity removable? f(x)= Ix-3I/x-3
Find the x values (if any) at which f is not continuous. Is this discontinuity removable? f(x)= Ix-3I/x-3
D Deleted member 4993 Guest Sep 11, 2009 #2 thepie said: Find the x values (if any) at which f is not continuous. Is this discontinuity removable? f(x)= Ix-3I/x-3 Click to expand... Investigate the behaviour of the function as you approach x = 3 - from the left and from the right. Use your graphing calculator. Please share with us your work/thoughts, indicating exactly where you are stuck - so that we know where to begin to help you
thepie said: Find the x values (if any) at which f is not continuous. Is this discontinuity removable? f(x)= Ix-3I/x-3 Click to expand... Investigate the behaviour of the function as you approach x = 3 - from the left and from the right. Use your graphing calculator. Please share with us your work/thoughts, indicating exactly where you are stuck - so that we know where to begin to help you
T thepie New member Joined Sep 11, 2009 Messages 2 Sep 11, 2009 #3 I'm not suppose to use my calculator, and I'm not sure how to start the problem.
D Deleted member 4993 Guest Sep 11, 2009 #4 thepie said: I'm not suppose to use my calculator, and I'm not sure how to start the problem. Click to expand... Then plot it by hand - that's not too difficult...
thepie said: I'm not suppose to use my calculator, and I'm not sure how to start the problem. Click to expand... Then plot it by hand - that's not too difficult...
B BigGlenntheHeavy Senior Member Joined Mar 8, 2009 Messages 1,577 Sep 11, 2009 #5 \(\displaystyle f(x) \ = \ \frac{|x-3|}{x-3}.\) \(\displaystyle If \ x \ is \ greater \ than \ three, \ then \ f(x) \ = \ 1.\) \(\displaystyle If \ x \ is \ less \ than \ three, \ then \ f(x) \ = \ -1.\) \(\displaystyle If \ x \ = \ three, \ then \ f(x) \ is \ undefined; \ the \ discontinuity \ is \ nonremovable.\)
\(\displaystyle f(x) \ = \ \frac{|x-3|}{x-3}.\) \(\displaystyle If \ x \ is \ greater \ than \ three, \ then \ f(x) \ = \ 1.\) \(\displaystyle If \ x \ is \ less \ than \ three, \ then \ f(x) \ = \ -1.\) \(\displaystyle If \ x \ = \ three, \ then \ f(x) \ is \ undefined; \ the \ discontinuity \ is \ nonremovable.\)