Convert polar form to rectangular form. (electrician studying phasors)

[jbjaidee]

Hello,

I am an electrician studying phasors (vectors) right now. I have not done this math for a long time and need a little help. If you could help me step by step that would be great! I'm not just looking for the answers, I would really like to know how to solve these problems. Thanks

Convert polar form phasor to rectangular form (use j operator for rectangular form):

120/30= 120 is the hypotenuse, 30 is the degree of angle (I think)


Convert rectangular form phasor to polar form:

5+j8= 5 is x, 8 is y (I think)

 

[Dr.Peterson]

Hello,

I am an electrician studying phasors (vectors) right now. I have not done this math for a long time and need a little help. If you could help me step by step that would be great! I'm not just looking for the answers, I would really like to know how to solve these problems. Thanks

Convert polar form phasor to rectangular form (use j operator for rectangular form):

120/30= 120 is the hypotenuse, 30 is the degree of angle (I think)


Convert rectangular form phasor to polar form:

5+j8= 5 is x, 8 is y (I think)

I saw your other question first, and was rather confused at first. Here you've more clearly stated the context. I presume your 120/30 is not meant to be a division, as it appears, but rather phasor form as you mention, 120∠30, meaning magnitude 120, angle 30°. This notation is not usually used in math proper, but in electrical engineering. And what you can j is what mathematicians usually call i, so you are asking about complex numbers.

Yes, you can think of 5 as x and 8 as y in your example.

You can read a little about the conversion here.

The magnitude is, as you called it, the hypotenuse of a right triangle, so you use r = sqrt(x^2 + y^2).

The angle is such that the tangent is y/x, so use theta = tan^-1(y/x). Then you have to check the quadrant, and adjust signs.

I'll answer your other question next, and perhaps show a little more detail if needed.