Converting Parametric Equations into Cartesian Equations

Oreo123

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Feb 20, 2016
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So I need help converting this parametric equation into a cartesian equation.
x=1/2(t2+1/t) y=1/2(t2-1/t2​)
 
So I need help converting this parametric equation into a cartesian equation.
x=1/2(t2+1/t) y=1/2(t2-1/t2​)
Are the expressions meant to be this:

. . . . .\(\displaystyle \mbox{a. }\, x\, =\, \dfrac{1}{2\,\left(t^2\, +\, \dfrac{1}{t}\right)}\, \mbox{ and }\, y\, =\, \dfrac{1}{2\,\left(t^2\, -\, \dfrac{1}{t^2}\right)}\)

...or this:

. . . . .\(\displaystyle \mbox{b. }\, x\, =\, \dfrac{1}{2\,\left(\dfrac{t^2\, +\, 1}{t}\right)}\, \mbox{ and }\, y\, =\, \dfrac{1}{2\,\left(\dfrac{t^2\, -\, 1}{t^2}\right)}\)

...or this:

. . . . .\(\displaystyle \mbox{c. }\, x\, =\, \dfrac{1}{2}\,\left(t^2\, +\, \dfrac{1}{t}\right)\, \mbox{ and }\, y\, =\, \dfrac{1}{2}\,\left(t^2\, -\, \dfrac{1}{t^2}\right)\)

...or this:

. . . . .\(\displaystyle \mbox{d. }\, x\, =\, \dfrac{1}{2}\,\left(\dfrac{t^2\, +\, 1}{t}\right)\, \mbox{ and }\, y\, =\, \dfrac{1}{2}\,\left(\dfrac{t^2\, -\, 1}{t^2}\right)\)

...or something else?

When you reply, please include a clear listing of your thoughts and efforts so far. Thank you! ;)
 
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