D danielvnl New member Joined Jan 3, 2013 Messages 38 Apr 13, 2013 #1 A person walks 20m to east, 50m to north and 15m at 75º from north to east. What's the total distance from the origin the person walked ? My answer ~64,0m Is the answer correct ?
A person walks 20m to east, 50m to north and 15m at 75º from north to east. What's the total distance from the origin the person walked ? My answer ~64,0m Is the answer correct ?
tkhunny Moderator Staff member Joined Apr 12, 2005 Messages 11,325 Apr 13, 2013 #2 Why don't you share with us how you arrived at this response?
D danielvnl New member Joined Jan 3, 2013 Messages 38 Apr 13, 2013 #3 y=15 cos75º y=3,9 x=15 sin75º x=14,4 50m to north + 3,9m = 53,9 20m to east + 14,4 = 34,4 (53,9)2 + (34,4)2 = D2 sqrt(4095) ~ 64m
y=15 cos75º y=3,9 x=15 sin75º x=14,4 50m to north + 3,9m = 53,9 20m to east + 14,4 = 34,4 (53,9)2 + (34,4)2 = D2 sqrt(4095) ~ 64m
D Deleted member 4993 Guest Apr 13, 2013 #4 danielvnl said: y=15 cos75º y=3,9 x=15 sin75º x=14,4 50m to north + 3,9m = 53,9 20m to east + 14,4 = 34,4 (53,9)2 + (34,4)2 = D2 sqrt(4095) ~ 64m Click to expand... Correct
danielvnl said: y=15 cos75º y=3,9 x=15 sin75º x=14,4 50m to north + 3,9m = 53,9 20m to east + 14,4 = 34,4 (53,9)2 + (34,4)2 = D2 sqrt(4095) ~ 64m Click to expand... Correct
