There are two Points A(-1,0) and B(0,3).
(a) Find the gradient of AB. Answer: This is 3-0/0-(-1) = 3
(b) Find the equation of AB. Answer: y=3x+c, Therefore c = 3, and the equation is y=3x + 3
(c) If length of AB is √h, what is value of h. Answer:AB^2 =√(-1-0)^2 + (0-3)^2, so h=10
(d) If the point (-5,k) lies on the line produced, fine value of k. Answer, y=3(-5)+3 = -12. Therefore k is (-5, -12)
(e) If line y=x+1 is the line of symmetry of the triangle ABC, find the co-ordinates of C
Need help on question (e) please. Many thanks in advance!
(a) Find the gradient of AB. Answer: This is 3-0/0-(-1) = 3
(b) Find the equation of AB. Answer: y=3x+c, Therefore c = 3, and the equation is y=3x + 3
(c) If length of AB is √h, what is value of h. Answer:AB^2 =√(-1-0)^2 + (0-3)^2, so h=10
(d) If the point (-5,k) lies on the line produced, fine value of k. Answer, y=3(-5)+3 = -12. Therefore k is (-5, -12)
(e) If line y=x+1 is the line of symmetry of the triangle ABC, find the co-ordinates of C
Need help on question (e) please. Many thanks in advance!