Could someone check my work?

[predondo]

(a/2^3)(64) - 12a : 6 solve exponents
(a/8)(64) - 12a : 6 a/8 x 64 simplifies to
8a - 12a :6
-4a/6 divide by common factor 2
-2a/3

 

[lev888]

(a/2^3)(64) - 12a : 6 solve exponents
(a/8)(64) - 12a : 6 a/8 x 64 simplifies to
8a - 12a :6
-4a/6 divide by common factor 2
-2a/3

According to precedence rules, what is the first operation here? 8a - 12a :6

 

[lookagain]

(a/2^3)(64) - 12a : 6 solve exponents
(a/8)(64) - 12a : 6 a/8 x 64 simplifies to
8a - 12a :6
-4a/6 divide by common factor 2
-2a/3

Line 1) You're already using "/" for division. Don't mix it with the ":" symbol. Supposing that the whole expression to the left of the colon is meant to
be divided by 6, you must have grouping symbols around that whole
expression.

Line 2) The expression at the left is not equal to the expression on the right, so
you cannot write "simplifies to."
Don't use "x" for multiplication, especially as you are already using parentheses
for that and for grouping.

Line 3) See the similar comment in the last sentence regarding your line 1.

Here is a suggestion based on the work you submitted:

[(a/2^3)(64) - 12a]/6 . . . . . Simplify the exponential expression.
[(a/8)(64) - 12a]/6 . . . . . . . Simplify (a/8)(64).
(8a - 12a)/6
-4a/6 . . . . . . . . . . . . . . . . . . Divide by the common factor of 2.
-2a/3

 

[predondo]

Line 1) You're already using "/" for division. Don't mix it with the ":" symbol. Supposing that the whole expression to the left of the colon is meant to
be divided by 6, you must have grouping symbols around that whole
expression.

Line 2) The expression at the left is not equal to the expression on the right, so
you cannot write "simplifies to."
Don't use "x" for multiplication, especially as you are already using parentheses
for that and for grouping.

Line 3) See the similar comment in the last sentence regarding your line 1.

Here is a suggestion based on the work you submitted:

[(a/2^3)(64) - 12a]/6 . . . . . Simplify the exponential expression.
[(a/8)(64) - 12a]/6 . . . . . . . Simplify (a/8)(64).
(8a - 12a)/6
-4a/6 . . . . . . . . . . . . . . . . . . Divide by the common factor of 2.
-2a/3

Thanks, I see that the way I wrote it out is confusing.