In how many ways may thirty different books be distributed tothree different libraries so that each library gets ten books?
Is this correct?
There are 30 difference books to be distributed to 3 different libraries in such way that each library gets 10 books.
Therefore, 30 books made into 3 equal parts in \(\displaystyle \dfrac{30!}{3!\, (10!)^3}\) ways.
They can be distrubuted to 3 libraries in \(\displaystyle \dfrac{30!}{3!\, (10!)^3}\, (3!)\, \mbox{ ways }\, =\, \dfrac{30!}{(10!)^3}\, \mbox{ ways}\)
Is this correct?
There are 30 difference books to be distributed to 3 different libraries in such way that each library gets 10 books.
Therefore, 30 books made into 3 equal parts in \(\displaystyle \dfrac{30!}{3!\, (10!)^3}\) ways.
They can be distrubuted to 3 libraries in \(\displaystyle \dfrac{30!}{3!\, (10!)^3}\, (3!)\, \mbox{ ways }\, =\, \dfrac{30!}{(10!)^3}\, \mbox{ ways}\)
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