C cmnalo Junior Member Joined Nov 5, 2006 Messages 61 Nov 22, 2006 #1 N(x) = 100,000 + 134x + 99.5x^2 - x^3 N'(x) = 134 + 199x -3x^2 How do I find the critical points from this first derivative?
N(x) = 100,000 + 134x + 99.5x^2 - x^3 N'(x) = 134 + 199x -3x^2 How do I find the critical points from this first derivative?
tkhunny Moderator Staff member Joined Apr 12, 2005 Messages 11,325 Nov 22, 2006 #2 {sigh} Who told you to forget algebra? Have you considered the Quadratic Formula? N'(x) = 0, right?
