S shivers20 Junior Member Joined Mar 3, 2006 Messages 68 Nov 7, 2007 #1 cxd=0, Therefore, Vector c is a scalar multiple of vector d? Can someone explain this to me? How would I go about finding if this is true. Thanks
cxd=0, Therefore, Vector c is a scalar multiple of vector d? Can someone explain this to me? How would I go about finding if this is true. Thanks
A arthur ohlsten Full Member Joined Feb 20, 2005 Messages 847 Nov 8, 2007 #2 CxD=0 lCl lDl sin @ =0 if C is not 0, and D is not 0, then @ must =0 degrees or 180 degrees. Then C and D must be scaler multiples. I hope thgis is acceptable to your instructor Arthur
CxD=0 lCl lDl sin @ =0 if C is not 0, and D is not 0, then @ must =0 degrees or 180 degrees. Then C and D must be scaler multiples. I hope thgis is acceptable to your instructor Arthur
