CYCLE-IN TRIANGLE

[hope]

HELLO!

PLEASE HELP ME ONCE AGAIN !!
MY NEW PROBLEM IS THISPROMISE WON${\displaystyle TWRIGHTFORSOMETIME)WELL:Ifthereiscyc\le \in scribed\in isosce\le s△\text{and}hiscenter÷sheight\in ratio(\propto \text{or}tion)12:5,\text{and}sof△is60cm,questionishowlongisthebaseof△(a\neg herside)??Res\underline{t}is50cm??How??I}$do not know how long is the height ,there is connection between ratio(12:5)and height and radius of cycle but...???
Please if you have patience ,show me step by step...
Thanks once more!!!

 

[Denis]

HELLO!
PLEASE HELP ME ONCE AGAIN !!
MY NEW PROBLEM IS THISPROMISE WON${\displaystyle TWRIGHTFORSOMETIME)WELL:Ifthereiscyc\le \in scribed\in isosce\le s△\text{and}hiscenter÷sheight\in ratio(\propto \text{or}tion)12:5,\text{and}sof△is60cm,questionishowlongisthebaseof△(a\neg herside)??Res\underline{t}is50cm??How??I}$do not know how long is the height ,there is connection between ratio(12:5)and height and radius of cycle but...???
Please if you have patience ,show me step by step...
Thanks once more!!!

C'mon hope...cycle? Is that a bicycle?
Do you mean CIRCLE?
Do you know what an isosceles triangle is?
Did you draw one, then put in a circle...just to see what it all looks like?

 

[hope]

I${\displaystyle amsos\text{or}ryf\text{or}mybadenglish,yesI}$ did mean circle.

WORK DONE :

12:5=2/3h:1/3h
12=2/3h
v=18
5=1/3h
h=15
18+15=33(height)
a=sqrt(60^2-33^2)(a=side)

a=50,1098??? I${\displaystyle knowt\hat{t}hisiswrongwaybutI}$ do not know
different.

r=a*sqrt(3)/6?? I` do not know how to make a connection between this
and ratio 12:5.

So if you want to help me OK if not that is OK to. Thank you for your constructive criticism.

[/code]

 

[Denis]

Sorry...didn't realise you had English problems;
I see you saw the solution at another site; good.

By the way, English is easy to "get"; my mother tongue
is French, but now I find English easier than French;
same should happen to you...

 

[Denis]

This may help you if you get similar problems (isosceles triangles involved).

Remember that an isosceles triangle is 2 right triangles stuck together;
as example, you can take 2 right triangles with dimensions 36-48-60,
stick them together along the side=48, and you get isosceles triangle
size 60-60-72, with height 48.

The inscribed circle is easy to figure out; if you let the sides of the right
triangle = a,b,c (b = height, c = hypotenuse), then the radius of circle is simply:
ab / (a + c).
For the 36-48-60, or isosceles 60-60-72 case: 36*48 / (36 + 60) = 18.

Hope that helps.

 

[Guest]

Related: http://www.sosmath.com/CBB/viewtopic.php?t=16926

 

[Denis]

WHAT?! The same question by Mathxyz? And on same day...

Hey hope, are you his girlfriend?

 

[hope]

No,do not worry I${\displaystyle am\neg hisgirliend.OK,I´th\in koweyouan\exp lanation.I}$am working and do not have very much time to spend on computer.I´also trying to go back to school but have ˝SOME˝hole in math , and I${\displaystyle wasl\infty k\in gf\text{or}somehelp.\mathrm{Sin}ceI}$ already explain I${\displaystyle do\neg haveallthetimeaess\to co\mp utersoI}$ just copy paste my Question and send it to all free math help forum because I${\displaystyle thoughtt\hat{\neg }somanypeop\le wo\underline{d}help.SOTHANKYOUALLONCEAGAIN.ANDJUSTONEMORETHING\left(ITDOESNOTJUSTIFIEDMEORMYBADENGLISH\right)but\sin ceI}$ was in a hurry and had a quick look in dictionary overlook a right word for my question I${\displaystyle putcyc\le \in steadof\circ \le .And\sin ceI}$ caused such ˝commotion˝I´will not write for some time.
By..

 

[Denis]

no "commotion" really, hope...
was all a bit funny

 

[hope]

OK!

Denis ˝baby˝ thanks!

Hope!