Hi All,
Here is another doosy. I am studying for the PCAT (Pharmacy exam) and I have to relearn all these simple concepts.
Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking?
I think that in order to solve this the distance for cyclist 2 must equal the distance for cyclist 1.
r1t1 = r2 t2
But something is just not clicking.
Thanks
DC6
Here is another doosy. I am studying for the PCAT (Pharmacy exam) and I have to relearn all these simple concepts.
Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking?
I think that in order to solve this the distance for cyclist 2 must equal the distance for cyclist 1.
r1t1 = r2 t2
But something is just not clicking.
Thanks
DC6