E EmmaC New member Joined Jan 22, 2011 Messages 3 Mar 15, 2012 #1 I have derived the Loss Function: L=E[(c/ab+c) (y0+ut) + (a/ab+c) (m0+vt-mt)]2 I need to derive dl/dm=0 I should end up with mt = .... Where would I begin? Last edited: Mar 15, 2012
I have derived the Loss Function: L=E[(c/ab+c) (y0+ut) + (a/ab+c) (m0+vt-mt)]2 I need to derive dl/dm=0 I should end up with mt = .... Where would I begin?
D Deleted member 4993 Guest Mar 15, 2012 #2 EmmaC said: I have derived the Loss Function: L=E[(C/ab+c) (y0+ut) + (a/ab+c) (m0+vt-mt)]^2 I need to derive dl/dm=0 I should end up with mt = .... Where would I begin? Click to expand... For a relevant answer, you really need to review your post and explain.... You have both C and c ..... are those same variable a/ab+c = b+c ..... is that what you meant? Use grouping symbols (parenthesis) and correct order of operation (PEMDAS) What is mO? .... is it m * O What is mt? .... is it m * t
EmmaC said: I have derived the Loss Function: L=E[(C/ab+c) (y0+ut) + (a/ab+c) (m0+vt-mt)]^2 I need to derive dl/dm=0 I should end up with mt = .... Where would I begin? Click to expand... For a relevant answer, you really need to review your post and explain.... You have both C and c ..... are those same variable a/ab+c = b+c ..... is that what you meant? Use grouping symbols (parenthesis) and correct order of operation (PEMDAS) What is mO? .... is it m * O What is mt? .... is it m * t
