Derivative of a function:

[rhombuster]

(2x − 5)⁴(x² + x + 1)<sup>5

Here's what I have so far:</sup>

(2x-5)⁴[d/dx(x²+x+1)⁵]+(x²+x+1)[d/dx(2x-5)⁴]

5(x²+x+1)⁴(2x+1)(2x-5)⁴ + 4(2x-5)³(2)(x²+x+1)⁵

How am I supposed to get it in to this form?

I'm completely off and I can't figure out why.

 

[Deleted member 4993]

(2x−5)⁴(x² + x + 1)<sup>5

Here's what I have so far:</sup>

(2x-5)⁴[d/dx(x²+x+1)⁵]+(x²+x+1)[d/dx(2x-5)⁴]

5(x²+x+1)⁴(2x+1)(2x-5)⁴ + 4(2x-5)³(2)(x²+x+1)⁵

How am I supposed to get it in to this form?

I'm completely off and I can't figure out why.

5(x²+x+1)⁴(2x+1)(2x-5)⁴ + 4(2x-5)³(2)(x²+x+1)⁵

= (2x-5)³ *[5(x² + x + 1)⁴ * (2x+1)(2x-5) + 8(x²+x+1)⁵]

= (2x-5)³ *(x² + x + 1)⁴[5 * (2x+1)(2x-5) + 8(x²+x+1)]

Now continue....