Derivative Problems

[dani_1121]

I can't figure out how to solve the following:

y= 2x/3x^2+1

y= x/x^2+1

y= 1/1-x^2

y= x^4+4x/-2

y= -1/x+1

y= 3x^3+7/2

 

[Deleted member 4993]

I can't figure out how to solve the following:

y= 2x/3x^2+1

y= x/x^2+1

y= 1/1-x^2

y= x^4+4x/-2

y= -1/x+1

y= 3x^3+7/2

I cannot make any sense out of your post.

What are you supposed to do/show?

Are those separate problems?

Also use grouping symbols to show correct order of operations.

As written the first line of equations reduce as following:

y = 2x/3x^2 + 1

y = 2*x/3*x^2 +1

y = 2/3 * x^3 + 1

If you meant to write:

\(\displaystyle y \ = \ \dfrac{2x}{3x^2 + 1}\)

Then you should have written:

y = 2x/(3x^2 + 1)

Also

Please share your work with us, indicating exactly where you are stuck - so that we may know where to begin to help you.