derivative question

It is all correct until you get [MATH]\frac{-c}{x(x+0)}[/MATH]; that is the final result, [MATH]-\frac{c}{x^2}[/MATH].
Why have you used the operation [MATH]\frac{\text{d}}{\text{d}x}[/MATH] after? The derivative is the limit, so when you have evaluated the limit you have finished.
 
Look at the first thing you wrote which was f'(x) = and it equals everything you wrote after that(except the end part). So when you arrived at -c/x2, that meant that f'(x) = -c/x2. You have to get a better understanding of the equality symbol.
 
tha
dunkelheit said:
It is all correct until you get [MATH]\frac{-c}{x(x+0)}[/MATH]; that is the final result, [MATH]-\frac{c}{x^2}[/MATH].
Why have you used the operation [MATH]\frac{\text{d}}{\text{d}x}[/MATH] after? The derivative is the limit, so when you have evaluated the limit you have finished.
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thank you for the help
 
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