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Given that f(3)=-1 and f '(3)=5, find an equations for the tangent line to the graph of y=f(x) at x=3

Alright, I do not know what this means. Can some one explain and provide an answer? text
 
badwithcalchica12 said:
Given that f(3)=-1 and f '(3)=5, find an equations for the tangent line to the graph of y=f(x) at x=3

Alright, I do not know what this means. Can some one explain and provide an answer? text

f(3) = -1 means we have a point on the function (3,-1)
f'(3) = 5 means we have the slope of the line at x = 3

The equation of the line can be written down without further trouble.

y - (-1) = 3*(x-3)
 
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