derivative

[volleyball11]

My brain just isn't working tonight...could somebody show me the steps to find the derivative of this problem? Thanks!

f(x)= 3xcosx / 2tanx

 

[Guest]

f(x)= 3xcosx / 2tanx

let u = 3xcosx and v = 2tanx

find du/dx and dv/dx for each of the above

f'(x) = (v. du/dx - u. dv/dx) / v^2


note each of the above can be seperated to ease the differential steps as well ie

u = a. b where a = 3x and b= cosx

then
da/dx = 3 , db/dx = (-sinx)

then du/dx = a . db/dx + b . da/dx

and the same for the other part.
Hope this gets you going

or rewrite the start as f(x) = 3 cosx cosx / ( 2 sinx)