derivatives: Find f'(x) for f(x) = t/(t+1)^2

[Becky4paws]

Find f'(x)

f(x) = t/(t+1)^2

f'(x) = (t+1)^2 (1) - [t(t+1)(2)]/(t+1)^4
f'(x) = (t+1)(2t)/(t+1)^4

I'm hoping it's correct.....

 

[peacefreak77]

your second line is correct, so i'm assuming you simplified it correctly

 

[skeeter]

Re: derivatives

Find f'(x)

f(x) = t/(t+1)^2

f'(x) = (t+1)^2 (1) - [t(t+1)(2)]/(t+1)^4
f'(x) = (t+1)(2t)/(t+1)^4

I'm hoping it's correct.....

your rough derivative is ok (watch your grouping symbols) ... your algebra is incorrect.

f'(x) = [(t+1)^2 (1) - t(t+1)(2)]/(t+1)^4

f'(x) = (t+1)[(t+1) - 2t]/(t+1)^4

f'(x) = (1-t)/(t+1)^3