x(t) = 12t^2+ 4t -12 a) Acceleration of the object? b) Acceleration of the object at t= 3s?
N Naomiliciously New member Joined May 22, 2021 Messages 1 May 22, 2021 #1 x(t) = 12t^2+ 4t -12 a) Acceleration of the object? b) Acceleration of the object at t= 3s?
N nasi112 Full Member Joined Aug 23, 2020 Messages 616 May 22, 2021 #2 First find the velocity [MATH]v = \frac{dx}{dt}[/MATH] Then, you can find the acceleration [MATH]a = \frac{dv}{dt}[/MATH]
First find the velocity [MATH]v = \frac{dx}{dt}[/MATH] Then, you can find the acceleration [MATH]a = \frac{dv}{dt}[/MATH]
D Deleted member 4993 Guest May 22, 2021 #3 Naomiliciously said: x(t) = 12t^2+ 4t -12 a) Acceleration of the object? b) Acceleration of the object at t= 3s? Click to expand... Please share your work/thoughts. Exactly where are you stuck?
Naomiliciously said: x(t) = 12t^2+ 4t -12 a) Acceleration of the object? b) Acceleration of the object at t= 3s? Click to expand... Please share your work/thoughts. Exactly where are you stuck?