C Crys0925 New member Joined Sep 17, 2007 Messages 1 Sep 17, 2007 #1 I am trying to figure out the derivative of 5 times the square root of x. 5(sqrt of x)The square root is what is throwing me off. Any help?
I am trying to figure out the derivative of 5 times the square root of x. 5(sqrt of x)The square root is what is throwing me off. Any help?
J jwpaine Full Member Joined Mar 10, 2007 Messages 719 Sep 17, 2007 #2 Crys0925 said: I am trying to figure out the derivative of 5 times the square root of x. The square root is what is throwing me off. Any help? Click to expand... derivative of \(\displaystyle \L5x^{2} = 2 \cdot 5x^{2-1} = 10x^{1} = 10x\)
Crys0925 said: I am trying to figure out the derivative of 5 times the square root of x. The square root is what is throwing me off. Any help? Click to expand... derivative of \(\displaystyle \L5x^{2} = 2 \cdot 5x^{2-1} = 10x^{1} = 10x\)
D Deleted member 4993 Guest Sep 18, 2007 #3 Crys0925 said: I am trying to figure out the derivative of 5 times the square root of x. 5(sqrt of x)The square root is what is throwing me off. Any help? Click to expand... \(\displaystyle \frac{d}{dx}(x^n) = nx^{(n-1)}\) in your case n = 1/2 so \(\displaystyle \frac{d}{dx}(x^{\frac{1}{2}}) = \frac{1}{2}x^{(\frac{1}{2}-1)} = \frac{1}{2}x^{(-\frac{1}{2})} = \frac{1}{(2sqrt{x})}\)
Crys0925 said: I am trying to figure out the derivative of 5 times the square root of x. 5(sqrt of x)The square root is what is throwing me off. Any help? Click to expand... \(\displaystyle \frac{d}{dx}(x^n) = nx^{(n-1)}\) in your case n = 1/2 so \(\displaystyle \frac{d}{dx}(x^{\frac{1}{2}}) = \frac{1}{2}x^{(\frac{1}{2}-1)} = \frac{1}{2}x^{(-\frac{1}{2})} = \frac{1}{(2sqrt{x})}\)
