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Derive a polynomial Formulua
- Thread starter kjbohn
- Start date
D
Deleted member 4993
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kjbohn said:Derive a polynomial formula for sum j^6, j=1 to N.
No work shown - no help shown.
Looks like your stuck at the begining - like your other posts.
To start off - pleas tell us the definition of "polynomial formula".
Please share your work with us, indicating exactly where you are stuck - so that we may know where to begin to help you.
There is plenty on line. Did you do a search?:
http://www.math.rutgers.edu/~erowland/sumsofpowers.html
http://www.math.rutgers.edu/~erowland/sumsofpowers.html
Thank you that website helped in giving a formulua of: (1/7)n^7+(1/2)n^6+(1/2)n^5-(1/6)n^3+(1/42)n. So for I have written out left and right hand summations that are left: a[sub:1fo0j646]7[/sub:1fo0j646](N+1)^7+a[sub:1fo0j646]6[/sub:1fo0j646](N+1)^6+a[sub:1fo0j646]5[/sub:1fo0j646](N+1)^5+a[sub:1fo0j646]4[/sub:1fo0j646](N+1)^4+a[sub:1fo0j646]3[/sub:1fo0j646](N+1)^3+a[sub:1fo0j646]2[/sub:1fo0j646](N+1)^2+a[sub:1fo0j646]1[/sub:1fo0j646](N+1)^1+a[sub:1fo0j646]0[/sub:1fo0j646](N+1)^0.the right side is: a[sub:1fo0j646]7[/sub:1fo0j646]N^7+a[sub:1fo0j646]6[/sub:1fo0j646]N^6+a[sub:1fo0j646]5[/sub:1fo0j646]N^5+a[sub:1fo0j646]4[/sub:1fo0j646]N^4+a[sub:1fo0j646]3[/sub:1fo0j646]N^3+a[sub:1fo0j646]2[/sub:1fo0j646]N^2+a[sub:1fo0j646]1[/sub:1fo0j646]N^1+a[sub:1fo0j646]0[/sub:1fo0j646]N^0. I think i have to add them together but I dont know how to go about that.
D
Deleted member 4993
Guest
kjbohn said:Thank you that website helped in giving a formulua of: (1/7)n^7+(1/2)n^6+(1/2)n^5-(1/6)n^3+(1/42)n. So for I have written out left and right hand summations that are left: a[sub:3m2g3gfq]7[/sub:3m2g3gfq](N+1)^7+a[sub:3m2g3gfq]6[/sub:3m2g3gfq](N+1)^6+a[sub:3m2g3gfq]5[/sub:3m2g3gfq](N+1)^5+a[sub:3m2g3gfq]4[/sub:3m2g3gfq](N+1)^4+a[sub:3m2g3gfq]3[/sub:3m2g3gfq](N+1)^3+a[sub:3m2g3gfq]2[/sub:3m2g3gfq](N+1)^2+a[sub:3m2g3gfq]1[/sub:3m2g3gfq](N+1)^1+a[sub:3m2g3gfq]0[/sub:3m2g3gfq](N+1)^0.the right side is: a[sub:3m2g3gfq]7[/sub:3m2g3gfq]N^7+a[sub:3m2g3gfq]6[/sub:3m2g3gfq]N^6+a[sub:3m2g3gfq]5[/sub:3m2g3gfq]N^5+a[sub:3m2g3gfq]4[/sub:3m2g3gfq]N^4+a[sub:3m2g3gfq]3[/sub:3m2g3gfq]N^3+a[sub:3m2g3gfq]2[/sub:3m2g3gfq]N^2+a[sub:3m2g3gfq]1[/sub:3m2g3gfq]N^1+a[sub:3m2g3gfq]0[/sub:3m2g3gfq]N^0. I think i have to add them together but I dont know how to go about that.
Are trying to use method of induction to prove the validity of the given formula?
However, that is not derivation.