I'm having a bit of difficulty with a problem from my Calculus IV class. I already solved this problem, but it doesn't match the answer given, and there's no justification for why that's the answer. The problem states:
My textbook says that, given a point in rectangular coordinates (x,y,z), Theta "measure the angular rotation from the x-axis to the ray containing the origin and the point (x,y,0)." and Phi "is the angle that the ray from the origin through point P makes with the z-axis."
So, rather than try and draw a 3D graph with perspective, I broke it apart into the xy-plane and yz-plane. In the xy-plane, the only coordinates that matter are Rho and Theta, and they can be I believe they can treated as the same as I would polar coordinates. Rho goes from 0 to 1 so we're dealing with a unit sphere, or some fraction thereof. Theta goes from 0 to pi/2. When Theta is 0, that's a straight line along the x-axis. And when Theta is pi/2, it's a straight line along the y-axis. Thus, I have a quarter circle in the first quadrant of the xy-plane. In the yz-plane, I applied similar reasoning. Based on the way my book draws their diagrams showing what angle Phi measures, I said that when Phi is 0, I'd have a straight line along the z-axis. And when Phi is pi/2, I'd have a straight line along the y-axis. Thus, I have a quarter circle in the first quadrant of the yz-plane.
And since I have a quarter circle in the first quadrants of both the xy-plane and the yz-plane, that suggests to me that the solid is a quarter of a sphere. However, the answer given is that it's a hemisphere. I don't have even the slightest clue how they might have come to that answer. Any help would be much appreciated.
This iterated integral uses spherical coordinates. Describe the solid determined by the limits of integration.
∫02π∫02π∫01f(ρ,θ,ϕ)ρ2sin(ϕ)dρdθdϕ
My textbook says that, given a point in rectangular coordinates (x,y,z), Theta "measure the angular rotation from the x-axis to the ray containing the origin and the point (x,y,0)." and Phi "is the angle that the ray from the origin through point P makes with the z-axis."
So, rather than try and draw a 3D graph with perspective, I broke it apart into the xy-plane and yz-plane. In the xy-plane, the only coordinates that matter are Rho and Theta, and they can be I believe they can treated as the same as I would polar coordinates. Rho goes from 0 to 1 so we're dealing with a unit sphere, or some fraction thereof. Theta goes from 0 to pi/2. When Theta is 0, that's a straight line along the x-axis. And when Theta is pi/2, it's a straight line along the y-axis. Thus, I have a quarter circle in the first quadrant of the xy-plane. In the yz-plane, I applied similar reasoning. Based on the way my book draws their diagrams showing what angle Phi measures, I said that when Phi is 0, I'd have a straight line along the z-axis. And when Phi is pi/2, I'd have a straight line along the y-axis. Thus, I have a quarter circle in the first quadrant of the yz-plane.
And since I have a quarter circle in the first quadrants of both the xy-plane and the yz-plane, that suggests to me that the solid is a quarter of a sphere. However, the answer given is that it's a hemisphere. I don't have even the slightest clue how they might have come to that answer. Any help would be much appreciated.