Ana.stasia
Junior Member
- Joined
- Sep 28, 2020
- Messages
- 118
the distance between points A and N is 5 ... why do you have d = 3 written down?
the slope between points A and N is [MATH]m=-\dfrac{4}{3}[/MATH]
the equation of the line passing through point A has slope perpendicular to segment AN
[MATH]y - 5 = m_{\perp}(x-2)[/MATH]
now, how does one determine a perpendicular slope?
mea culpa ...Read the problem.
To continue the method you are using, you can solve the first equation for C and substitute that in the second equation. Then you can try to solve for A/B (because only the ratio can be determined - or you could take B=1 and solve for A).Determine the equations of lines containing point A (2,5) and whose distance from point N (5,1) is equal to 3.
I honestly have no idea how to connect the two formulas i have in squares.
View attachment 25077
note the horizontal distance between A and N is 3 [MATH]\implies x = 2[/MATH] is one line that passes through A and is a distance of 3 from N.
It would probably help a lot if you could also post a screenshot of the problem from your book (in addition of course to the screenshot of your attempts). By the way, who is the author of your book?Determine the equations of lines containing point A (2,5) and whose distance from point N (5,1) is equal to 3.
I honestly have no idea how to connect the two formulas i have in squares.
View attachment 25077