If you want to draw something, go to http://www.twiddla.com/137515 and draw stuff.
This is in Chapter 7 called Right-Angled Trigonometry, except it doesn't have a right angle.
I tried this and it didn't work:
tan 50deg = O/A = x/10 = 11.92
Edit: I tried cos 50 = a/h = 10/x
x*(cos 50 ) = 10
x= 10/cos 50
=15.56
The answer at the back is 7.78m if it helps.
Edit: I have some more questions...
I put it in my calculator and it says this:
9' 2' 39.88'
Answer is this:
9' 03'
...and last ones (2 questions in picture):
15 & 16)
For 15 I have figured out s but not t.
For t I have:
tan 68deg = O/A = s/t = 41.69/t
tan 68t = 41.69
68t = tan[sup:3pbbk75r]-1[/sup:3pbbk75r] 41.69
t= 1.30
But I'm way off, the answer is 16.84
For 16 I have this for alpha :
sin alpha = o/h = 79/82
but the answer is 74' 27' and when I put 79/82 into the calculator i get 0' 57'
I'm not sure about beta because it doesn't say that there is another right angle next to the other right angle.
The length of a base in an isosceles triangle is 10cm. Determine the length of the equal sides of the triangle if each make an angle of 50deg with the base.
This is in Chapter 7 called Right-Angled Trigonometry, except it doesn't have a right angle.
I tried this and it didn't work:
tan 50deg = O/A = x/10 = 11.92
Edit: I tried cos 50 = a/h = 10/x
x*(cos 50 ) = 10
x= 10/cos 50
=15.56
The answer at the back is 7.78m if it helps.
Edit: I have some more questions...
Evaluate each of the following, correct to the nearest minute
11 a) sin[sup:3pbbk75r]-1[/sup:3pbbk75r] 0.1572
I put it in my calculator and it says this:
9' 2' 39.88'
Answer is this:
9' 03'
...and last ones (2 questions in picture):
15 & 16)
For 15 I have figured out s but not t.
For t I have:
tan 68deg = O/A = s/t = 41.69/t
tan 68t = 41.69
68t = tan[sup:3pbbk75r]-1[/sup:3pbbk75r] 41.69
t= 1.30
But I'm way off, the answer is 16.84
For 16 I have this for alpha :
sin alpha = o/h = 79/82
but the answer is 74' 27' and when I put 79/82 into the calculator i get 0' 57'
I'm not sure about beta because it doesn't say that there is another right angle next to the other right angle.