Deternime the coordinates of points on the curve y=5x^2...

[wind]

Hi, I just wanted to know if these are the correct steps to follow to solve this question

Deternime the coordinates of all points on the curve y=5x^2 - 4x^3 where the tangent passes throught ( 0,0)

1) find the slope of the tangent
2) find equation for tangent
3) make the 2 equations, tangent and curve, equal because they will share the same y value at some point
4) solve for x
5) plug into curve equation to find y

I just had a test and I am anxious to see if I did it right.

Thanks

 

[galactus]

Was this one of your problems?.

Did you get (5/8,125/128) as one of your points?.

 

[wind]

Was this one of your problems?.

yes but the numbers were different

Did you get (5/8,125/128) as one of your points?.

ya, so I did it right then?

 

[galactus]

Yeah, apparently. I got x=5/8 and x=0 as the 2 points.

 

[wind]

Thanks galactus