J jeflow New member Joined Jan 21, 2006 Messages 6 Jan 21, 2006 #1 1 Find the integral S from -1 to 1 of 4/1+x^2. -1 I just integrated the top and bottom to get 4x/ x+(x^3/3) i then got 4/1(1/3) - 4/1(1/3) to equal 0. Is this correct
1 Find the integral S from -1 to 1 of 4/1+x^2. -1 I just integrated the top and bottom to get 4x/ x+(x^3/3) i then got 4/1(1/3) - 4/1(1/3) to equal 0. Is this correct
pka Elite Member Joined Jan 29, 2005 Messages 11,978 Jan 21, 2006 #2 jeflow said: 1 Find the integral S from -1 to 1 of 4/1+x^2. -1 I just integrated the top and bottom to get 4x/ x+(x^3/3) NO! Click to expand... \(\displaystyle \L \int {\frac{4}{{1 + x^2 }}dx = 4\arctan (x)} +c\)
jeflow said: 1 Find the integral S from -1 to 1 of 4/1+x^2. -1 I just integrated the top and bottom to get 4x/ x+(x^3/3) NO! Click to expand... \(\displaystyle \L \int {\frac{4}{{1 + x^2 }}dx = 4\arctan (x)} +c\)
