Hello. Only part (ii) instructs to discuss continuity. Are you asking for help at x=0, with the function in part (ii)?(Discuss the continuity of these functions)
I do not understand it myself but that was just the question: To discuss the continuity of these functions. It these was used, maybe there are more than one; if there are not, may be it was just error of typingHello. Only part (ii) instructs to discuss continuity. Are you asking for help at x=0, with the function in part (ii)?
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Hi. Just to confirm, which part are you currently working on?I do not understand it myself
No, that's not what I'd said.What you are trying to say is that, the statement is not clear regarding the [questions] to be [answered]?
No, that's not what I'd said.
I understand the exercise, but I don't like their wording "the continuity of the function" because that phrase implies that the function is continuous.
We cannot tell just by looking at the piecewise definitions in parts (ii) and (iii) whether either of those functions are continuous or not, at x=0. The reason why is because we haven't been given any values for the parameters m and a.
Perhaps there exists some value for m that makes the first function continuous. Maybe there's more than one value that works. Or, maybe no value of m will make the function continuous at x=0.
Likewise, the second function may or may not be continuous at x=0. If it can be, then there are one or more values of a that produce continuity.
You need to investigate and then discuss issues like these:
Whether each function can be continuous at x=0If it can be continuous, then what value(s) of m or a are requiredIf it can not be made continuous, then state why not
f(0) = ln(a) in part (iii)you have to compute f(0), But in this question, it has been given as ln a
Yes, 0/(-1)=0 in both parts (ii) and (iii). That tells us the limit is zero. But, the limit doesn't tell us anything about the value of f(0). Remember, in a limit, x never takes on the value it approaches. In your limits, x gets as close to zero as you would like, closer and closer, but x will never equal 0.limit x tends to zero of f(x) can be easily obtained by putting x=0 in the function...to get 0/1=0
You're talking about part (iii). Your conclusion is incorrect. There is a value for the parameter a, such that ln(a) equals zero.conclude that since f(0) is not equal to [the limit,] then the function is discontinuous at x=0, regardless the value of a
I agree in part (ii) that no value of m will make 1/m equal zero. Therefore, the function in part (ii) cannot be made continuous.if you look at the questions 2 and 3 well enough, no value of a or m can make the function continuous.
yes, its over. thanksHi ugudansom. Were you able to finish part (iii)?