Using standard Law of Quotients for differentiation, calculate G'(x) and then G'(0).Given that F(0) = 2 and F'(0) = -1, find G'(0), where G(x) = x/1+sec(F(2x))
According to the image that you posted \(\large\bf G(x)=\dfrac{x}{1+\sec(F(2x))}\).Given that F(0) = 2 and F'(0) = -1, find G'(0), where G(x) = x/1+sec(F(2x))