Differential equation

[layd33foxx]

dy/dx=(e^x-e^-x)²
=e^2x+2+e^-2x

∫dy= ∫e^2x+2+e^-2x dx
y=(1/2)e^2x+2x-(1/2)e^-2x+C
:?:
I'm not sure if I have to keep going,
I get stuck here.

 

[Deleted member 4993]

dy/dx=(e^x-e^-x)²
=e^2x+2+e^-2x

∫dy= ∫e^2x+2+e^-2x dx
y=(1/2)e^2x+2x-(1/2)e^-2x+C
:?:
I'm not sure if I have to keep going,
I get stuck here.

This is it ... you're done.

You may want to check your answer - by differentiating. You should get back the original function if your work is correct.

 

[layd33foxx]

Yay thank you