Anthonyk2013
Junior Member
- Joined
- Sep 15, 2013
- Messages
- 132
Stuck on this question. Can't figure out where they get X(4X+9Y) in the answer from the book. I attached my solution.
Assuming I am reading the problem correctly, I believe the your answer is (almost)
correct: Given
2x2y + 3x3=sin(y)
then
y' = \(\displaystyle \frac{x\, (4y\, +\, 9x)}{cos(y)\, -\, 2x^2}\)
You dropped a minus sign and, IMO, the answer book has a typo