W wessicataylor New member Joined Oct 4, 2011 Messages 3 Oct 4, 2011 #1 what is the value of the integral of (dx/(x-1)) from a=0 to b=1
W wessicataylor New member Joined Oct 4, 2011 Messages 3 Oct 4, 2011 #2 does this integral diverge or is there a way to solve it?
burakaltr Junior Member Joined Aug 26, 2011 Messages 126 Oct 4, 2011 #3 wessicataylor said: what is the value of the integral of (dx/(x-1)) from a=0 to b=1 Click to expand... It's not too difficult if you know that u'/u = dln(u)/du so ln(abs(x-1))+c is your integral, do not forget the absolute sign so how will you evaluate when a=0 to b=1 ?
wessicataylor said: what is the value of the integral of (dx/(x-1)) from a=0 to b=1 Click to expand... It's not too difficult if you know that u'/u = dln(u)/du so ln(abs(x-1))+c is your integral, do not forget the absolute sign so how will you evaluate when a=0 to b=1 ?
W wessicataylor New member Joined Oct 4, 2011 Messages 3 Oct 4, 2011 #4 then it becomes ln(0)-ln(1), which diverges, right?
burakaltr Junior Member Joined Aug 26, 2011 Messages 126 Oct 4, 2011 #5 wessicataylor said: then it becomes ln(0)-ln(1), which diverges, right? Click to expand... At x=1 1/(1-x) is not defined --> closes to an asymptote which is vertical. http://www.wolframalpha.com/input/?i=1/(1-x)
wessicataylor said: then it becomes ln(0)-ln(1), which diverges, right? Click to expand... At x=1 1/(1-x) is not defined --> closes to an asymptote which is vertical. http://www.wolframalpha.com/input/?i=1/(1-x)
burakaltr Junior Member Joined Aug 26, 2011 Messages 126 Oct 4, 2011 #6 http://www.wolframalpha.com/input/?i=Integrate+1/(1-x)+,from+0+to+1 Last edited: Oct 5, 2011