H hgaon001 New member Joined May 17, 2009 Messages 39 Nov 3, 2009 #1 Find the Coefficient of x^4 in (2x^2 + 6)^12 i try the formula for the binomial theorem but im not gettin the correct answer.. helpppp please
Find the Coefficient of x^4 in (2x^2 + 6)^12 i try the formula for the binomial theorem but im not gettin the correct answer.. helpppp please
D daon Senior Member Joined Jan 27, 2006 Messages 1,284 Nov 3, 2009 #2 \(\displaystyle (2x^2 + 6)^{12} = \sum_{k=0}^{12} {12 \choose k}(2x^2)^k(6)^{12-k}\) For what k will you have \(\displaystyle x^4\)? Evaluate the coefficent for that k.
\(\displaystyle (2x^2 + 6)^{12} = \sum_{k=0}^{12} {12 \choose k}(2x^2)^k(6)^{12-k}\) For what k will you have \(\displaystyle x^4\)? Evaluate the coefficent for that k.
H hgaon001 New member Joined May 17, 2009 Messages 39 Nov 3, 2009 #3 I dont know how to find K.. cuz i was goin over some examples and sum said like 2k=4.. and others had 2(12-k)=4..
I dont know how to find K.. cuz i was goin over some examples and sum said like 2k=4.. and others had 2(12-k)=4..
D DrMike Full Member Joined Mar 31, 2009 Messages 251 Nov 3, 2009 #4 daon said: For what k will you have \(\displaystyle x^4\)? Evaluate the coefficent for that k. Click to expand...
daon said: For what k will you have \(\displaystyle x^4\)? Evaluate the coefficent for that k. Click to expand...